The coordinates of points P and Q are (4, 3) and (2, -1) respectively. Find the shortest distance between P and Q.

A.

10\(sqrt{2}\)

B.

4\(sqrt{5}\)

C.

5\(sqrt{2}\)

D.

2\(sqrt{5}\)

Correct answer is D

p(4, 3) Q(2 - 1)

distance = \(\sqrt{(x_2 - x_1)^2 + (Y_2 - y_1)^2}\)

= \(\sqrt{(2 - 4)^2 + (-1 - 3)^2}\)

= \(\sqrt{(-2)^2 = (-4)^2}\)

= \(\sqrt{4 + 16}\)

= \(\sqrt{20}\)

= \(\sqrt{4 \times 5}\)

= 2\(\sqrt{5}\)