The angle of elevation of the top of a vertical tower from a point A on the ground is 60o. From a point B, 2 units of distance further away from the foot of the tower, the angle of elevation of the tower is 45o. Find the distance of A from the foot of the tower

A.

3 + \(\sqrt{3}\)

B.

5 + \(\sqrt{3}\)

C.

3 - \(\sqrt{3}\)

D.

1

E.

\(\sqrt{3}\) - 1

Correct answer is D

No explanation has been provided for this answer.