Solve the simultaneous equations $\frac{2}{x} - {\frac{3}{y}}$ = 2, $\frac{4}{x} + {\frac{3}{y}}$ = 10

x = $\frac{3}{2}$ , y = $\frac{3}{2}$

x = $\frac{1}{2}$ , y = $\frac{3}{2}$

x = $\frac{-1}{2}$ , y = $\frac{-3}{2}$

x = $\frac{1}{3}$ , y = $\frac{3}{2}$

Correct answer is B

$\frac{2}{x} - {\frac{3}{y}}$ = 2.....(1)

$\frac{4}{x} + {\frac{3}{y}}$ = 10 ... (2)

(1) + (2):

$\frac{6}{x}$ = 12 $\to$ x = $\frac{6}{12}$

x = $\frac{1}{2}$

put x = $\frac{1}{2}$ in equation (i)

= 4 - $\frac{3}{y}$ = 2

= 4 - 2

= $\frac{3}{y}$

therefore y = $\frac{3}{2}$

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