30o
45o
60o
90o
105o
Correct answer is B
sec2 θ + tan2 θ = 3 Where 1 + tan2 θ = sec2 θ 1 + tan2 θ + tan2 θ = 3 2 tan2 θ = 2 tan2 θ = 1
tanθ = √1
where √1 = 1
tanθ = 1 And tan 45° = 1 ∴ θ = 45°
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