\(\sqrt\frac{3T - K}{M}\)
\(\sqrt\frac{3T - M}{K}\)
\(\sqrt\frac{3T + K}{M}\)
Correct answer is B
T = \(\frac{KR^2 + M}{3}\) 3T = KR2 + M KR2 = 3T - M R2 = \(\frac{3T - M}{K}\) R = \(\sqrt\frac{3T - M}{K}\)
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