\(\sqrt{3}\) units
3 units
\(\sqrt{41 + 20 \sqrt{2}}\) units
\(\sqrt{41 - 20 \sqrt{2}}\) units
Correct answer is C
Force to the east = 5 units
force to the North - east = 4 units.
Resultant of the two forces is the square root
52 + 42 = 41 and plus the sum of its resistance
5 x 4\(\sqrt{2}\) = 20\(\sqrt{2}\)
= \(\sqrt{41 + 20 \sqrt{2}}\) units
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