The following table relates the number of objects f corresponding to a certain size x. What is the average size of an object?
$\begin{array}{c|c} f & 1 & 2 & 3 & 4 & 5 \\ \hline x & 1 & 2 & 4 & 8 & 16\end{array}$

$\frac{31}{15}$

$\frac{31}{5}$

$\frac{129}{5}$

$\frac{43}{5}$

$\frac{16}{5}$

Correct answer is D

F = 1, 2, 3, 4, 5

x = 1, 2, 4, 8, 16

fx = 1, 4, 12, 32, 80, 3f = 15

(average size) = $\frac{\sum fx}{\sum f}$

= $\frac{129}{15}$

= $\frac{43}{5}$

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The following table relates the number of objects f corresponding to a certain size x. What is the average size of an object?
$\begin{array}{c|c} f & 1 & 2 & 3 & 4 & 5 \\ \hline x & 1 & 2 & 4 & 8 & 16\end{array}$

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The following table relates the number of objects f corresponding to a certain size x. What is the average size of an object?
$\begin{array}{c|c} f & 1 & 2 & 3 & 4 & 5 \\ \hline x & 1 & 2 & 4 & 8 & 16\end{array}$