PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find

PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15^o find < QRS

75^o

37\(\frac{1}{2}\)^o

127\(\frac{1}{2}\)^o

105^o

Correct answer is D

PSO = 90^o(angle in a semicircle)

SPO = 180^o - (90^o + 15^o) = 75^o

< QRS = 108^o - 75^o

= 105^o(opposite angles in cyclic quadrilateral are supplementary)

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PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find < QRS

Aptitude Tests

PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15^o find < QRS