PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15^o find < QRS

75^o

37 $\frac{1}{2}$ ^o

127 $\frac{1}{2}$ ^o

105^o

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Correct answer is D

PSO = 90^o(angle in a semicircle)

SPO = 180^o - (90^o + 15^o) = 75^o

< QRS = 108^o - 75^o

= 105^o(opposite angles in cyclic quadrilateral are supplementary)

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PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find < QRS

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PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15^o find < QRS