Using the circuit diagram above. Calculate the total charge in the circuit
A.
80\(\mu C\)
B.
35\(\mu C\)
C.
20\(\mu C\)
D.
16\(\mu C\)
Correct answer is D
C - \(C_1 + C_2 = 2 + 6 = \mu F\)
\(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2}\)
C = \(\frac{8}{5 \mu F}\)
Q = CV
= \(\frac{8}{5} \times 10 = 16\mu C\)