A body starts with an initial velocity of 20 m/s and moves with a uniform acceleration, a, for 15 seconds. Which of the following equations represents the distance, S, traveled?
300 + 56\(\frac{a}{2}\)
300 + \(\frac{225a}{2}\)
300 + \(\frac{225}{2a}\)
300a + \(\frac{225}{2}\)
Correct answer is B
u = 20 ms-1, t = 15 s
\(S = ut + 1/2 at^2\)
S = 20(15) + \(\frac{1}{2}× a × 15^2\)
∴ S = 300 + 225\(\frac{a}{2}\)