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Find the missing numerator 5x+1 - \(\frac{3}{...

Find the missing numerator 5x+1 - 31x - 7x1x21 = ?x+1.

A.

-1

B.

x - 1

C.

3(15x)x+1

D.

1

E.

3(1 - 5x)

Correct answer is D

5x+131x7x1x21=?x+1

5(x1)3((x+1))7x1x21

= 5x5+3x+37x1x21

= x1x21

= x1(x1)(x+1)

= 1x+1.

The numerator = 1.