Three numbers, x, y and z are connected by the relationships y = \(\frac{4x}{9}\) + 1. If x = 99, Find z = \(\frac{4y}{9}\) + 1

6\(\frac{1}{3}\)

176\(\frac{4}{9}\)

None of the above

Correct answer is C

y = \(\frac{4x}{9}\) + 1, z = \(\frac{4y}{9}\) + 1, z = \(\frac{4}{9}\)(\(\frac{4}{9}\) x + 1) + 1

= [\(\frac{4}{9}\)(\(\frac{4}{9}\)(99) + 1]

= \(\frac{4}{9}\)(45) + 1

= 21

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Three numbers, x, y and z are connected by the relationships y = \(\frac{4x}{9}\) + 1. If x = 99, Find z = \(\frac{4y}{9}\) + 1

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