3√10
3√5
√26
√13
Correct answer is D
2x - y .....(i)
x + y.....(ii)
from (i) y = 2x - 4
from (ii) y = -x + 2
2x - 4 = -x + 2
x = 2
y = -x + 2
= -2 + 2
= 0
x1 = 2
y1 = 0
x2 = 4
y2 = 3
Hence, dist. = √(y2−y1)2+(x2−x1)2
= √(3−0)2+(4−2)2
= √32+22
= √13
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