\(\frac{x^2 + y^2} {(x - y)^2}\)
\(\frac{2y^3} {y^2 - x^2}\)
\(\frac{3x^2 + y^2} {(2x - y)^2}\)
\(\frac{x^2 + y^2} {(x^2 - y)}\)
Correct answer is B
\(\frac{x^2 + y^2 + xy}{x + y}\) - \(\frac{x^2 + y^2}{x -y}\)
= \(\frac{-y^3 - y^3}{x^2 - y^2}\)
= \(\frac{2y^3}{x^2 - y^2}\)
= \(\frac{2y^3}{y^2 - x^2}\)