1
6
\(\frac{1}{27}\)
\(\frac{4}{3}\)
Correct answer is C
\(\frac{3^n - 3^{n - 1}}{3^3 \times 3^n - 27 \times 3^{n - 1}}\) = \(\frac{3^n - 3^{n - 1}}{3^3(3^n - 3^{n - 1})}\) = \(\frac{3^n - 3^{n - 1}}{27(3^n - 3^{n - 1})}\) = \(\frac{1}{27}\)
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