Three consecutive terms of a geometric progression are give as n - 2, n and n + 3. Find the common ratio 

A.

\(\frac{3}{2}\)

B.

\(\frac{2}{3}\)

C.

\(\frac{1}{2}\)

D.

\(\frac{1}{4}\)

Correct answer is A

\(\frac{h}{n - 2} = \frac{n + 3}{n}\)

n\(^2\) = (n + 3) (n - 2) 

n\(^2\) = n\(^2\) + n - 6

n\(^2\) + n - 6 - n\(^2\) = 0

n - 6 = 0

n = 6

Common ratio: \(\frac{n}{n - 2} = \frac{6}{6 - 2} = \frac{6}{4}\) = \(\frac{3}{2}\)