4√3
4√3
√32
1√3
2√3
Correct answer is A
cot(90−θ)sin2θ
cot(90−θ)=tanθ
∴
\tan \theta = \frac{\sqrt{3}}{3}
\sin \theta = \frac{1}{2} \implies \sin^{2} \theta = \frac{1}{4}
\frac{\cot(90 - \theta)}{\sin^{2} \theta} = \frac{\sqrt{3}}{3}\div\frac{1}{4}
= \frac{4}{\sqrt{3}}
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