Which of the formula below represents the general terms of the following set of numbers(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)......) for n = 1, 2, 3, 4.......?

A.

\(\frac{2}{n + 1}\)

B.

(-1)n + 1 \(\frac{2}{n + 1}\)

C.

(-1)n \(\frac{2}{n + 1}\)

D.

\(\frac{n}{2n - 1}\)

E.

(-1)n\(\frac{n}{2n - 1}\)

Correct answer is C

(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)......)

nthterm is (-1)n\(\frac{2}{n + 1}\)

Since (-1)n will always be negative for n = odd