-1, 2
1, 2
2, 1
2, -1
Correct answer is D
2x−1−3y−1=4;4x−1+y−1=1
Let x−1 = a and y−1= b
2a - 3b = 4 .......(i)
4a + b = 1 .........(ii)
(i) x 3 = 12a + 3b = 3........(iii)
2a - 3b = 4 ...........(i)
(i) + (iii) = 14a = 7
∴ a = 714 = 12
From (i), 3b = 2a - 4
3b = 1 - 4
3b = -3
∴ b = -1
From substituting, 2−1=x−1
∴ x = 2
y−1=−1,y=−1
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