\(\frac{x}{y}\)
xy
\(\frac{x}{y}\)
(xy)-1
Correct answer is C
Simplify (\(\frac{1}{x^{-1}} + \frac{1}{y^{-1}}\))-1 = (\(\frac{1}{x^{-1}} + \frac{1}{y^{-1}}\))-1
= (x + y)-1 = \(\frac{(x)}{y}\)
= \(\frac{x}{y}\)
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