O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
A.
68o
B.
64o
C.
42o
D.
32o
E.
22o.
Correct answer is A
TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
= 180 - 112
= 68o