$\begin{array}{c|c} x & 2 & 4 & 6 & 8\\ \hline f & 4 & y & 6 & 5 \end{array}$
If the mean of the above frequency distribution is 5.2, find y

2, 1

1, 2

1, 5

5, 2

Correct answer is C

Mean $\bar{x}$ = $\frac{\sum fx}{\sum f}$

= $\frac{5.2}{1}$

= $\frac{8 + 4y + 36 + 40}{4 + y + 6 + 5}$

= $\frac{5.2}{1}$

= $\frac{84 + 4y}{15 + y}$

= 5.2(15 + y)

= 84 + 4y

= 5.2 x 15 + 5.2y

= 84 + 4y

= 78 + 5.2y

= 84 = 4y

= 5.2y - 4y

= 84 - 78

1.2y = 6

y = $\frac{6}{1.2}$

= $\frac{60}{12}$

= 5

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