The nth term of a sequence is Tn = 5 + (n - 1)2. Evaluate T4 - T6

A.

30

B.

16

C.

-16

D.

-30

View answer & explanation

Correct answer is C

T4 = 5 + (4 - 1)2; where n = 4

= 5 + (3)2 = 5 + 9

= 14

T = 5 + (6 - 1)2

where n = 6

= 5 + (5)2

= 5 + 25 = 30

T4 + T6 = 14 - 30

= -16

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