In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm...
In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
x
x2y
yx2
y2x
Correct answer is D
\frac{x}{x+y}=\frac{y}{x+CE}\\ xy + xCE = xy + y^2\\ ∴xCE = y^2\\ CE=\frac{y^2}{x}
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