In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm...
In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
x
\(\frac{x^2}{y}\)
\(\frac{y}{x^2}\)
\(\frac{y^2}{x}\)
Correct answer is D
\(\frac{x}{x+y}=\frac{y}{x+CE}\\
xy + xCE = xy + y^2\\
∴xCE = y^2\\
CE=\frac{y^2}{x}\)
Similar Questions
The square root of a number is 2k. What is half of the number ...
Simplify \(\frac{3}{5} \div \left(\frac{2}{7} \times \frac{4}{3} \div \frac{4}{9}\right)\) ...
What is the n-th term of the sequence 2, 6, 12, 20...?...
Solve the simultaneous equations for x in x2 + y - 8 = 0, y + 5x - 2 = 0...
Given that logx 64 = 3, evaluate x log\(_2\)8...
Arrange the following numbers in descending orders of magnitude: 22three, 34five, 21six...
Evaluate \(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\)...
A binary operation Δ is defined by a Δ b = a + 3b + 2. Find (3 Δ 2) Δ 5 ...