If 9\(^{(x - \frac{1}{2})} = 3^{x2}\)
Find x
\(\frac{1}{2}\)
1
2
3
Correct answer is B
9(x - \(\frac{1}{2}\)) 3x2 = 32(x - \(\frac{1}{2}\)) = 3x2 ∴ 2(x - \(\frac{1}{2}\)) = x2 2x - 1 = x2 hence x2 - 2x + 1 = 0 (x - 1)(x - 1) = 0 x = 1
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