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Find the equation whose roots are \(\frac{2}{3}and \frac{-1}...

Find the equation whose roots are \(\frac{2}{3}and \frac{-1}{4}\)

A.

\(12x^2-5x+2=0\)

B.

\(12x^2-11x+2=0\)

C.

\(x^2-\frac{11}{12}x+2=0\)

D.

\(x^2+\frac{11}{12}x-2=0\)

E.

\(12x^2+11x+2=0\)

Correct answer is A

x\(^2\) - (sum of given roots)x + (product of given roots ) = 0
x\(^2\) - (\(\frac{2}{3} + \frac{-1}{4}\))x + (\(\frac{2}{3} * \frac{-1}{4}\)) = 0

x\(^2\) - (\(\frac{8 - 3}{12}\))x + (\(\frac{- 2}{12}\))

x\(^2\) - \(\frac{5}{12}\)x + \(\frac{- 2}{12}\)

multiply through by the LCM 12

12 * x\(^2\) - 12 * \(\frac{5}{12}\)x + 12 * \(\frac{- 2}{12}\)

12x\(^2\) - 5x - 2 = 0