$\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 & 11 - 15 & 16 - 20 & 21 - 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array}$
Estimate the median of the frequency distribution above

10 $\frac{1}{2}$

11 $\frac{1}{2}$

Correct answer is C

Median = L + [ $\frac{\frac{N}{2} - f}{fm}$ ]h

N = Sum of frequencies

L = lower class boundary of median class

f = sum of all frequencies below L

fm = frequency of modal class and

h = class width of median class

Median = 11 + [ $\frac{\frac{50}{2} - 21}{20}$ ]5

= 11 + ( $\frac{25 - 21}{20}$ )5

= 11 + ( $\frac{(4)}{20}$ )

11 + 1 = 12

See all Mathematics questions & answers

See more JAMB questions & answers

$\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 & 11 - 15 & 16 - 20 & 21 - 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array}$
Estimate the median of the frequency distribution above

Similar Questions

Aptitude Tests

Class Interval1−56−1011−1516−2021−25Frequency6152072\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 & 11 - 15 & 16 - 20 & 21 - 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array} Estimate the median of the frequency distribution above

Similar Questions

Aptitude Tests

$\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 & 11 - 15 & 16 - 20 & 21 - 25 \\ \hline Frequency & 6 & 15 & 20 & 7 & 2\end{array}$
Estimate the median of the frequency distribution above