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\(\begin{array}{c|c} \text{Class Interval} & 1 - 5 & 6 - 10 ...

Class Interval15610111516202125Frequency6152072
Estimate the median of the frequency distribution above

A.

1012

B.

1112

C.

12

D.

13

Correct answer is C

Median = L + [N2ffm]h

N = Sum of frequencies

L = lower class boundary of median class

f = sum of all frequencies below L

fm = frequency of modal class and

h = class width of median class

Median = 11 + [5022120]5

= 11 + (252120)5

= 11 + ((4)20)

11 + 1 = 12