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Make K the subject of the relation T = \(\sqrt{\frac{TK - H}...

Make K the subject of the relation T = TKHKH

A.

K = H(T21)T2T

B.

K = HT(T1)2

C.

K = H(T2+1)T

D.

K = H(T1)T

Correct answer is A

T = TKHKH

Taking the square of both sides, give

T2 = TKHKH

T2(K - H) = TK - H

T2K - T2H = TK - H

T2K - TK = T2H - H

K(T2 - T) = H(T2 - 1)

K = H(T21)T2T