\(\frac{1100}{3}\)km
\(\frac{2200}{3}\)km
\(\frac{22000}{3}\)km
Correct answer is C
Angular difference = 45° + 15° = 60°.
\(D = \frac{60°}{360°} \times 2 \times \frac{22}{7} \times 7000\)
= \(\frac{22000}{3} km\)
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