In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. ...
In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. If the bisector of and M meets NO at P, calculate NP.
4.8 units
7.2 units
8.0 units
18.0 units
Correct answer is B
bisector theorem:
|MN||MO| = |PO||NP|
taking the bisected angle:x and y = |ON|=12
: x+y= 12
x = 12 - y
|PO| = 12 - y
64= 12−yy
6y = 4 (12-y)
6y = 48 - 4y
= 4.8
Recall that x+y= 12
12 - 4.8 =7.2