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In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. ...

In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. If the bisector of and M meets NO at P, calculate NP.

A.

4.8 units

B.

7.2 units

C.

8.0 units

D.

18.0 units

Correct answer is B

bisector theorem:

|MN||MO| = |PO||NP|

taking the bisected angle:x and y = |ON|=12

: x+y= 12

x =  12 - y

|PO| = 12 - y

64= 12yy

6y = 4 (12-y)

6y = 48 - 4y

= 4.8

Recall that x+y= 12

12 - 4.8 =7.2