In how many ways can a committee of 2 women and 3 men be ...
In how many ways can a committee of 2 women and 3 men be chosen from 6 men and 5 women?
100
200
30
50
Correct answer is B
A committee of 2 women and 3 men can be chosen from 6 men and 5 women, in \(^{5}C_{2}\) x \(^{6}C_{3}\) ways
= \(\frac{5!}{(5 - 2)!2!} \times {\frac{6!}{(6 - 3)!3!}}\)
= \(\frac{5!}{3!2!} \times {\frac{6!}{3 \times 3!}}\)
= \(\frac{5 \times 4 \times 3!}{3! \times 2!} \times {\frac{6 \times 5 \times 4 \times 3!}{3! \times 3!}}\)
= \(\frac{5 \times 4}{1 \times 2} \times {\frac{6 \times 5 \times 4}{1 \times 2 \times 3}}\)
= 10 x \(\frac{6 \times 20}{6}\)
= 200
Find the probability that a number selected from the number 30 to 50 inclusive is a prime ...
Obtain a maximum value of the function f(x) x3 - 12x + 11...
The nth term of a sequence is n2 - 6n - 4. Find the sum of the 3rd and 4th terms....
Given that tan x = 5/12, what is the value of sin x + cos x ?...
Given that 3x - 5y - 3 = 0, 2y - 6x + 5 = 0 the value of (x, y) is...