Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k

A.

-4

B.

-2

C.

-1

D.

\(-\frac{1}{4}\)

View answer & explanation

Correct answer is A

Substituting for x in the equation
\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)

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