The probability that a student passes a physics test is \(\frac{2}{3}\). If he takes three physics tests, what is the probability that he passes two of the tests?

A.

\(\frac{2}{27}\)

B.

\(\frac{3}{27}\)

C.

\(\frac{4}{27}\)

D.

\(\frac{5}{3}\)

Correct answer is C

Pass(P) = \(\frac{2}{3}\), Fail(F) = \(\frac{1}{3}\)

T = P.P.F ==> \(\frac{2}{3} \times \frac{2}{3} \times \frac{1}{3}\) = \(\frac{4}{27}\)