\(\frac{2}{27}\)
\(\frac{3}{27}\)
\(\frac{4}{27}\)
\(\frac{5}{3}\)
Correct answer is C
Pass(P) = \(\frac{2}{3}\), Fail(F) = \(\frac{1}{3}\)
T = P.P.F ==> \(\frac{2}{3} \times \frac{2}{3} \times \frac{1}{3}\) = \(\frac{4}{27}\)
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