1
2
3
4
Correct answer is A
\(\int^{\frac{\pi}{4}}_0sec^2 \theta d \theta\)
= \([\tan \theta]_{0} ^{\frac{\pi}{4}}\)
= \(\tan \frac{\pi}{4} - \tan 0\)
= \(1 - 0\)
= 1.
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