The gradient of the straight line joining the points P(5, -7) and Q(-2, -3) is
\(\frac{1}{2}\)
\(\frac{2}{5}\)
\(-\frac{4}{7}\)
\(-\frac{2}{3}\)
Correct answer is C
PQ = \(\frac{y_1 - y_0}{x_1 - x_0}\) = \(\frac{-3 - (-7)}{-2 - 5}\) = \(\frac{-3 + 7}{-2 - 5}\) = \(\frac{4}{-7}\)