12
p - 2r
1p−2r
2pp−2r
Correct answer is A
(p−r)2−r22p2−4pr = (p−r)(p−r)−r22p2−4pr\ = p2−2pr+r2−r22p(p−2r = p2−2pr2p(p−2r) = p(p−2r)2p(p−2r) = 12
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