Simplify $\frac{(p - r)^2 - r^2}{2p^2 - 4pr}$

$\frac{1}{2}$

p - 2r

$\frac{1}{p - 2r}$

$\frac{2p}{p - 2r}$

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Correct answer is A

$\frac{(p - r)^2 - r^2}{2p^2 - 4pr}$

= $\frac{(p - r)(p - r) - r^2}{2p^2 - 4pr}$ \

= $\frac{p^2 - 2pr + r^2 - r^2}{2p(p - 2r}$

= $\frac{p^2 - 2pr}{2p(p - 2r)}$

= $\frac{p(p - 2r)}{2p(p - 2r)}$

= $\frac{1}{2}$

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Simplify $\frac{(p - r)^2 - r^2}{2p^2 - 4pr}$