12
p - 2r
1p−2r
2pp−2r
Correct answer is A
(p−r)2−r22p2−4pr
= (p−r)(p−r)−r22p2−4pr\
= p2−2pr+r2−r22p(p−2r
= p2−2pr2p(p−2r)
= p(p−2r)2p(p−2r)
= 12
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