\(\frac{\sqrt{2}}{7}cm\)
\(3\frac{1}{2}cm\)
7cm
\(7\sqrt{2}cm\)
Correct answer is D
\(A=\pi r^2 \Rightarrow 77 = \frac{22}{7} \times \frac{r^2}{1}\Rightarrow r^2 = \frac{77\times 7}{22} \Rightarrow r^2 = \frac{49}{2}\\
\Rightarrow r = \sqrt{\frac{49}{2}}=\frac{7}{\sqrt{2}}. Since D = 2r ∴ D = 2 \times \frac{7}{\sqrt{2}} = \frac{14}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = 7\sqrt{2}cm\)
The solution to the simultaneous equations 3x + 5y = 4, 4x + 3y = 5 is...
If O is the centre of the circle, < POS equls ...
Find the value of t, if the distance between the points P(–3, –14) and Q(t, –5) is...
In the diagram, NQ//TS, <RTS = 50\(^o\) and <PRT = 100\(^o\). Find the value of <NPR...
Solve \(\frac{1}{x + 1}\) - \(\frac{1}{x + 3}\) = \(\frac{1}{4}\)...
Simplify; \(\frac{1}{2}\sqrt{32} - \sqrt{18} \sqrt{2}\)...
The length of an arc of a circle of radius 3.5 cm is 1\(\frac{19}{36}\) cm. Calculate, correct...