A body of mass 5kg initially at rest is acted upon by two mutually perpendicular forces 12N and 5N as shown in fig.3. If the particle moves in the direction QA, calculate the magnitude of the acceleration
A.
0.40ms-2
B.
1.40ms-2
C.
0.26ms-2
D.
2.60ms-2
E.
3.40ms-2
Correct answer is D
R = \(\sqrt{12^2 + 5^2}\)
R = 13N and R = F = ma
13 = 5 x a
= 2.60ms\(^{-2}\)