A block of mass 2.04kg resting on a smooth horizontal plane is acted upon simultaneously by two-forces, 10N due North and 10N due East. The magnitude of the acceleration produced by the force on the block is
0.10ms-2
7.07ms-2
10.00ms-2
14.10ms-2
20.00ms-2
Correct answer is B
R = \(\sqrt {10^2 + 10^2}\)
R = 14.14N
R = F = ma
14.14 = 2 x a
a = 7.07ms-1