A straight wire 15cm long, carrying a current of 6.0A is in a uniform field of 0.40T. What is the force on the wire when it is at right angle to the field
0.46N
0.35N
0.36N
0,24N
Correct answer is C
F = BIL = 0.4 x 6 x \(\frac{15}{100}\)
= 0.36N
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