\(\frac{1}{3},-3\)
\(-\frac{1}{3},-3\)
\(-\frac{1}{3},3\)
\(\frac{1}{3},3\)
Correct answer is C
3x\(^2\) - 8x - 3 = 0
3x\(^2\) - 9x + x - 3 = 0
3x(x - 3) + 1(x - 3) = 0
(3x + 1)(x - 3) = 0
3x = -1 \(\implies\) x = \(-\frac{1}{3}\)
or x = 3.
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