(\(\frac{g}{fh}\))2
f2g2h2
\(\frac{5}{4}\)goh\(\frac{7}{9}\)
\(\frac{g^2}{f^5h^7}\)
\(\frac{1}{f^2h^2}\)
Correct answer is A
f\(\frac{1}{2}\)g2h\(\frac{1}{2}\) \(\div\) f\(\frac{5}{2}\)goh\(\frac{7}{3}\) = f\(\frac{1}{2}\) - \(\frac{5}{2}\) g2 - 0 h\(\frac{1}{2}\) - \(\frac{7}{3}\)
f-2 g2 h-2
= \(\frac{g^2}{f^2h^2}\)
= (\(\frac{g}{fh}\))2
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