Given that p^{\(\frac{1}{3}\)} = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation

q = p\(\sqrt{r}\)

q = p³r

q = pr³

q = pr^{\(\frac{1}{3}\)}

Correct answer is D

p^{\(\frac{1}{3}\)} = \(\frac{3\sqrt{q}}{r}\)(cross multiply)

3\(\sqrt{q}\) = r x 3\(\frac{\sqrt{q}}{r}\)(cross multiply)

3\(\sqrt{q}\) = r x 3\(\sqrt{p}\) cube root both side

q = 3\(\sqrt{r}\) x p

q = r^{\(\frac{1}{3}\)}p = pr^{\(\frac{1}{3}\)}

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Given that p\(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation

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Given that p^{\(\frac{1}{3}\)} = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation