2x = 3(y - 1)
4x - y = 1
3y + 2x = 3
3y = 2 (x + 3)
Correct answer is A
24\(_x\) = 31\(_y\)
\(2 \times x^1 + 4 \times x^0 = 3 \times y^1 + 1 \times y^0\)
\(2x + 4 = 3y + 1 \implies 2x = 3y + 1 - 4\)
\(2x = 3y - 3 = 3(y - 1)\)
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