A load of 20N on a wire of cross-sectional area 8 x 10-7m2, produces an extension of 10m2. calculate Young's modulus for the material of the wire if its length is 3m

A.

7.0 x 1011Nm-2

B.

7.5 x 1011Nm-2

C.

8.5 x 1011Nm-2

D.

9.0 x 1011Nm-2

Correct answer is B

Young's modulus = \(\frac{F}{A}\) \(\div\) \(\frac{e}{L}\)

= \(\frac{20}{8 \times 10^{-7}}\) \(\div\) \(\frac{10^{-4}}{3}\)

= 7.5 x 1011Nm-2