The distance between the fixed points of a mercury-in-glass thermometer is 30 cm. Determine the temperature when the mercury level is 10.5 cm above the lower fixed point
28.6ºC
30.0 ºC
35.0 ºC
40.5 ºC
Correct answer is C
\(\frac{10.5-0}{30-0}\) = \(\frac{c-0}{100-0}\)
\(\frac{10.5}{30}\) = \(\frac{c}{100}\)
cross multiply:
10.5 * 100 = 30c
35.0 ºC = c