An object is placed 10cm in front of a concave mirror of focal length 15cm. What is the position and nature of the image formed?
30cm and virtual
6cm and real
6cm and virtual
30cm and real
Correct answer is A
F = \(\frac{uv}{u + v}\)
15 = \(\frac{10 \times v}{10 + v}\)
v = -30cm