Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

1,391.

Which of the diagrams above shows the position at which a small ball-bearing is in neutral equilibrium?

A.

A

B.

B

C.

C

D.

D

Correct answer is D

Neutral Equilibrium: If the body neither returns to its original position nor increases its displacement further, it will simply adopt its new position.

Examples of neutral equilibrium

  • Ball moving on the ground.
  • Motion of sphere.
  • A roller.
  • A pencil lying horizontally.
  • An egg lying horizontally on a flat surface.
1,392.

A progressive wave is represented by \( y = 10 \text{Sin} (1000\pi t - \frac{\pi x}{34}) \) . two layers of the wave separated by 153cm have a phase difference of?

A.

2700

B.

450

C.

900

D.

1800

E.

No Correct Option

Correct answer is C

Comparing \( y = 10 \text{Sin} (1000\pi t - \frac{\pi x}{34}) \) with y = A sin (ωt - ϕ)

where ϕ = \(\frac{2\pi x}{λ}\)

comparing:  \(\frac{2\pi x}{λ}\) = \( \frac{\pi x}{34}\)

λ = 34 \(\times\) 2 = 68

: ϕ =  \(\frac{2\pi x}{λ}\) =  \(\frac{2\pi \times 153}{68}\)

ϕ = 4.5\(\pi\) rad = 810° or 90°

since sin 810° or 90° = 1

1,393.

A radioactive substance has a half life of 20 days. What fraction of the original radioactive nuclei will remain after 80 days?

A.

\( \frac{1}{32} \)

B.

\( \frac{1}{16} \)

C.

\( \frac{1}{8} \)

D.

\( \frac{1}{4} \)

Correct answer is B

80 days = 4 half lives (i.e 4 x 20dqs = 80dq)

But the fraction always left by any radioactive material after 4 half lives is

\( \left ( \frac{1}{2} \right)^4 = \frac{1}{16} \)

1,394.

A 120V, 60W lamp is to be operated on 220V ac supply mains. calculate the value of non inductive resistance that would be required to ensure that the lamp is run on correct value

A.

100Ω

B.

200Ω

C.

300Ω

D.

500Ω

Correct answer is B

Power of the lamp = 60W;  

\(I = {\frac{P}{V}}\)

\(I = {\frac{60}{120}}\) = \(0.5A\)

\(R = {\frac{V}{I}}\)

\(R_mains\) = \(\frac{220}{0.5}\) = \(440\Omega\)

\(R_lamp\) = \(\frac{120}{0.5}\) = \(240\Omega\)

\(\therefore\) The non-inductive resistance to keep the lamp = \((440 - 240)\Omega\)

= \(200\Omega\)

1,395.

Lenz's law is a law of conservation of

A.

electric charge

B.

electric current

C.

Energy

D.

Momentum

Correct answer is C

Lenz's lew of electrical magnetic induction is usefully referred to as the law of conservation of energy