If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
600
290
990
900
Correct answer is B
From the relation refractive index = Sin \( \left(\frac{A+Dm}{2}\right) \)
Where A = refractive angle = 600, Sin\( \left(\frac{A}{2}\right) \)
\( \implies 1.4 = \frac{\text{Sin}\left(\frac{60^0 + Dm}{2}\right)}{\text{Sin}\left(\frac{60}{2}\right)} \\
= \frac{\text{Sin}\left(\frac{60 + Dm}{2}\right)}{\text{Sin}30^0} \\
= \frac{\text{Sin}\left(\frac{60 + Dm}{2}\right)}{0.5}\\
\text{Therefore} 1.4 \times 0.5 = \text{Sin}\left(\frac{60 + Dm}{2}\right) \\
\text{Therefore} \left(\frac{60 + D_m}{2}\right)= \text{Sin}^{-1} 0.7000 \\
= 44^0 12^1 \\
60^0 + D_m = 88^0 24^1 \\
D_m = 88^0 24^1 - 60^0 \\
= 28^0 24 \\
29^0 \)
12cm
20cm
18cm
15cm
Correct answer is C
For Hooke's law F = Ke
\( \implies F/e = K \\
f1/e1=f2/e2 \\
\text{Let the original length} = t_0 \\
\text{therefore} e1 = (36 - t_0)cm ; e2 = (46 - t_0)cm \\
\text{if f1} = 40N \text{f2} = 60N \\
\text{Then } \frac{40}{36 - t_0} = \frac{60}{45 - t_0} \\
\implies 40(45 - t_0) = 60(36 - t_0) \\
\text{therefore } 1800 - 40t_0 \\
2160 - 60t_0 \\
60t_0 - 40t_0 = 2160 - 1800 \\
20t_0 = 360 \\
t_0 = 18cm \)
If two inductors of inductances 3H and 6H are arranged in series, the total inductance is
9.0H
18.0H
0.5H
2.0H
Correct answer is A
l =l1 + l2 = 3 + 6 = 9H
400N
200N
100N
800N
Correct answer is D
let the masses of the two objects be M1 and M2
and their distance apart = r
Therefore the force acting F1 = \( \frac{GM1M2}{r^2} \)
for a new distance of r/2, we have a force of
F2 = \( \frac{GM2M2}{r/2} \\
\text{Thus } F1 \times r^2 = GM1M1 \text{and} \\
F2 \times (r/2)^2 = GM1M1 \\
\text{Since } GM1M1 = GM1M1 \\
\implies F1 \times r^2 = F2 \times (r/2)^2 \\
\text{Therefore } 200 \times r^2 = F2 \times r^2/4 \\
F2 = \frac{4 \times 200 \times r^2}{r^2} = 800N \)
The velocity of sound in air will be doubled if it's absolute temperature is
Quadrupled
Constant
Halved
Doubled
Correct answer is A
In general, the velocity of sound in air varies directly as the square root of temperature measured in kelvin.
That V \( \propto \sqrt{T} \implies V^2 \propto T. \\
\text{Therefore} \frac{V^2_1}{T_1} = \frac{V^2_2}{T_2} \\
\text{Thus Let } V_1 = 4m/s \\
T_1 = 10K \\
\text{Therefore } V_2 = 2V_1 = 8m/s \\
\implies \frac{4^2}{10} = \frac{8^2}{T_2} \\
T_2 = \frac{64 \times 10}{16} = 40K\\
T_2 = 4T_1 \)
Thus when the velocity of sound in air is doubled, it's absolute temperature will be quadrupled.