When a man moves toward a plane mirror at a speed of 6m/s, the distance the man and his image increased at a speed of?

2 m/s

4 m/s

12 m/s

14 m/s

Correct answer is C

d = y, s = 6 m/s (The Man & Plane Mirror)

d – δy, s = (5 &ndash ;6) m/s (The Man and Image)

d₂ ÷ s₁ = d₂ ÷ s₂, y ÷ 6 = 2y ÷ s + 6

Y (s + 6) = 2y × 6

s + 6 = 12

S_o = 12 – 6 = 6

Since S + 6 = 0

Then, S = 6 (substitute the value of S i.e S = 6)

Into S + 6 = 0

∴S_o = S + 6 = 6 + 6 = 12 m/s

∴ S = 12 m/s

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When a man moves toward a plane mirror at a speed of 6m/s, the distance the man and his image increased at a speed of?

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